Using ::javaClass syntax does not result in a Class<T> instance, as someone might expect.
Instead, it creates a property reference of type KProperty0<Class<T>>, which is almost never correct and can lead to unexpected behavior and hard-to-detect bugs.

Provides a fix to use a direct .javaClass call or ::class.java syntax instead.

Example 1: Expression receiver

When ::javaClass is used on an expression, the quick-fix replaces it with a regular .javaClass call:

  fun test(a: String) {
      val classRef = a::javaClass  // KProperty0<Class<String>>
      println(classRef)            // Prints "property javaClass", not "class java.lang.String"
  }

After the quick-fix is applied:

  fun test(a: String) {
      val classRef = a.javaClass  // Class<String>
      println(classRef)           // Prints "java.lang.String"
  }

Example 2: Type receiver

When ::javaClass is used on a type, the quick-fix replaces it with ::class.java:

  fun test() {
      val classRef = String::javaClass  // KProperty1<String, Class<String>>
      println(classRef)                 // Prints "property javaClass", not "class java.lang.String"
  }

After the quick-fix is applied:

  fun test() {
      val classRef = String::class.java  // Class<Any>
      println(classRef)                  // Prints "class java.lang.String"
  }