Record can be converted to class

Reports record classes and suggests converting them to ordinary classes.

This inspection makes it possible to move a Java record to a codebase using an earlier Java version by applying the quick-fix to this record.

Note that the resulting class is not completely equivalent to the original record:

The resulting class no longer extends java.lang.Record, so instanceof Record returns false.
Reflection methods like Class.isRecord() and Class.getRecordComponents() produce different results.
The generated hashCode() implementation may produce a different result because the formula to calculate record hashCode is deliberately not specified.
Record serialization mechanism differs from that of an ordinary class. Refer to Java Object Serialization Specification for details.

Example:

record Point(int x, int y) {}

After the quick-fix is applied:

final class Point {
  private final int x;
  private final int y;

  Point(int x, int y) {
    this.x = x;
    this.y = y;
  }

  public int x() { return x; }

  public int y() { return y; }

  @Override
  public boolean equals(Object obj) {
    if (obj == this) return true;
    if (obj == null || obj.getClass() != this.getClass()) return false;
    var that = (Point)obj;
    return this.x == that.x &&
           this.y == that.y;
  }

  @Override
  public int hashCode() {
    return Objects.hash(x, y);
  }

  @Override
  public String toString() {
    return "Point[" +
           "x=" + x + ", " +
           "y=" + y + ']';
  }
}

This inspection only reports if the language level of the project or module is 16 or higher.

New in 2020.3

Inspection Details
Available in:	IntelliJ IDEA 2023.3, Qodana for JVM 2023.3
Plugin:	Java, 233.SNAPSHOT

Last modified: 13 July 2023