Unnecessary supertype qualification

Reports super member calls with redundant supertype qualification.

Code in a derived class can call its superclass functions and property accessors implementations using the super keyword. To specify the supertype from which the inherited implementation is taken, super can be qualified by the supertype name in angle brackets, e.g. super<Base>. Sometimes this qualification is redundant and can be omitted. Use the 'Remove explicit supertype qualification' quick-fix to clean up the code.

Examples:

open class B {
    open fun foo(){}
}

class A : B() {
    override fun foo() {
       super<B>.foo() // <== redundant because 'B' is the only supertype
    }
}

interface I {
    fun foo() {}
}

class C : B(), I {
    override fun foo() {
        super<B>.foo() // <== here <B> qualifier is needed to distinguish 'B.foo()' from 'I.foo()'
    }
}

After the quick-fix is applied:

open class B {
    open fun foo(){}
}

class A : B() {
    override fun foo() {
       super.foo() // <== Updated
    }
}

interface I {
    fun foo() {}
}

class C : B(), I {
    override fun foo() {
        super<B>.foo()
    }
}

Inspection Details
Available in:	IntelliJ IDEA 2023.3, Qodana for JVM 2023.3
Plugin:	Kotlin, @snapshot@

Last modified: 13 July 2023